Skip<TSource> Method

System.Linq

public static IEnumerable<TSource> Skip<TSource>(this IEnumerable<TSource> source, int count)

Bypasses a specified number of elements in a sequence and then returns the remaining elements.

Syntax

public static IEnumerable<TSource> Skip<TSource>(
    this IEnumerable<TSource> source,
    int count
)

Parameters

source: Type: System.Collections.Generic.IEnumerable<TSource>
The IEnumerable<T> to return elements from.
count: Type: int
The number of elements to skip before returning the remaining elements.

Returns

Type: System.Collections.Generic.IEnumerable<TSource>
An System.Collections.Generic.IEnumerable<T> that contains the elements that occur after the specified index in the input sequence.

Exceptions

ArgumentNullException: source is null.
ArgumentOutOfRangeException: count is negative.

Examples

The following code example demonstrates how to use the Skip method to skip a specified number of elements from a list of integers.

// Sample data
List<int> numbers = new List<int> { 5, 4, 2, 9, 3, 10, 8 };

// Skip the first 3 elements
IEnumerable<int> remainingNumbers = numbers.Skip(3);

// Output the remaining elements
Console.WriteLine("Elements after skipping the first 3:");
foreach (int number in remainingNumbers)
{
    Console.WriteLine(number);
}
// Expected output:
// Elements after skipping the first 3:
// 9
// 3
// 10
// 8

Remarks

If count is less than or equal to zero, the original sequence is returned.

If count is greater than the number of elements in source, an empty sequence is returned.

The Skip method is implemented by using deferred execution.